Procedure 2: Place a 250 g mass into the felt bottomed cart on the level track.

Question

Procedure 2: Place a 250 g mass into the felt bottomed cart on the level track. Hook a string on the end of the cart, pass it over the pulley, and hang the mass-holder (mass 50g) on the other end. Slowly add small slotted masses to the mass-holder until the cart begins to slide.

Refer to procedure 2. Assume the mass of the cart is m, and the mass hanging on the end of the string, M, is the maximum mass needed to just balance friction.

Suppose now that mass 722 g is added to m, the mass of the cart. Find the new mass M needed to keep the system at equilibrium.

Explanation / Answer

0.255*(2.33+0.25+0.722)*9.8 =M*9.8 so, M = 0.842 kg - 0.05 = 0.792 kg = 792 g

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