Three small spherical masses are located in a plane at the positions shown below

Question

Three small spherical masses are located in a plane at the positions shown below. The masses are Q=0.300 kg, R=0.600 kg, and S=0.500 kg. Calculate the moment of inertia (of the 3 masses) with respect to an axis perpendicular to the xy plane and passing through x=0 and y=-1. [Since the masses are of small size, you can neglect the contribution due to moments of inertia about their centers of mass.]

Three small spherical masses are located in a plane at the positions shown below. The masses are Q=0.300 kg, R=0.600 kg, and S=0.500 kg. Calculate the moment of inertia (of the 3 masses) with respect to an axis perpendicular to the xy plane and passing through x=0 and y=-1. [Since the masses are of small size, you can neglect the contribution due to moments of inertia about their centers of mass.]

Explanation / Answer

I = m*r^2 Now the distances from the rotation point Q = sqrt(13) point R distance = sqrt(17) point S = sqrt(29) So I = 0.300kg*13 + 0.600kg*17 + 0.500kg*29= 28.6kg-m^2

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