A group of students performed the same \"Ohm\'s Law\" experiment that you did in

Question

A group of students performed the same "Ohm's Law" experiment that you did in class. They obtained the following results:
Trial ?V (volts) I (mA)
1 1.00 4.8
2 2.00 9.0
3 3.00 14.3
4 4.00 19.0
5 5.00 23.3
where ?V is the voltage difference across the resistor and I is the current traveling through the resistor at the same time.
(a) Analyze the data. (You will not submit this spreadsheet. However, the results will be needed later in this problem.)
(i) Enter the above data into an Excel spreadsheet.
(ii) Make a plot of the voltage difference vs. current.
(iii) Use the trendline option in Excel to fit the data of voltage difference versus current to get the slope and intercept.

(b) Determine the slope and y-intercept of your graph, and report these values below. (Use ohm for ?.)

I put 4.7 ohm and I only got partial credit and for y intercept I put -.02 and it says I need units wiith and I m not sure what units to put down next to y intercept.

Explanation / Answer

I did the same thing you did...plot current as a function of ?V, not ?V as a function of current, and got the same result. Swap your x and y values in the plot's data series and I think the bot will like your results better. (Geez, I hate those things!) The second time I got y = 0.0279x + 0.0019. (That makes sense, because 1/35.877 = 0.0279 and 0.069/35.877 = 0.0019, appropriately rounded, solving for the slope and intercept as 1/(original slope) and (x intercept) of the original graph.)

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