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A group of students performed the same experiment that you did in class. They ob

ID: 1332130 • Letter: A

Question

A group of students performed the same experiment that you did in class. They obtained the results that are displayed in red below. Analyze this data by performing the indicated calculations. Remember that there is a link to your lab manual at the bottom of this question, if you need to refer back to the lab background and introduction.

Use the exact values you enter to make later calculations.

Data Measured Data: Kirchhoff's Laws - Voltage and Current in Circuits The voltage across and the current through each resistor are shown in the schematic diagrams below. B A R3 R3 R2 R5 R2 Voltage, A B1.533 V Current, Point A 0.039 A Current, Point B 0.039 A Table 1 Resistor Voltage (V) Current (A) R1 = 10 R2 = 4.7 Ra = 33 Ra = 4.7 R5 = 10 Rtotal 0.127 0.127 1.279 0.127 0.127 1.533 0.012 0.027 0.039 0.027 0.012 0.039

Explanation / Answer

Answer : In parallel

Since Galvanometer is a very sensitive instrument therefore it can’t measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low resistance known as "shunt" resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes     through the shunt. In this way a galvanometer is converted into ammeter and can measure heavy currents without fully deflected.

The maximum current that ammeter can read is given by finding the voltage across the galvanometer is

Vg =Ig*Rg =(6.42*10-3)(23.3ohm) =0.149V

Now currrent throguh the shunt is Is = (I-Ig) =(0.039-6.42*10-3) =0.032A

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