A pendulum bob of mass m is initially at a vertical distance y1 above a table. A

Question

A pendulum bob of mass m is initially at a vertical distance y1 above a table. After it is released, it swings to a lowest point, at distance y2 above the table, and then almost to its initial height v, on the other side. By how much does the bob's PE at its highest point exceed its PE at its lowest point? What is the kinetic energy of the bob as it passes through its lowest point? Calculate answers to the above questions if the mass of the bob is 1.0 kg, the highest point is 72 cm above the table, and the lowest point is 31 cm above the table.

Explanation / Answer

a)PE higher than PE lower= mg(y1-y2) b)Kinetic energy at lower point= PE at higher point=mg(y1-y2) c)mg(y1-y2)=1*9.8*0.41=4.018 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.