An air capacitor is made from two flat parallel plates 1.50mm apart. The magnitu

Question

An air capacitor is made from two flat parallel plates 1.50mm apart. The magnitude of charge on each plate is 0.0180uc when the potential difference is 200V .

1. What is the area of each plate?
Answer in m^2

2. What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric field strength of 3*10^6 V/m.)
Answer in V

Explanation / Answer

Q=CV =>C=0.018*10^-6/200=9*10^-11F C=eA/d e0=8.854x10-12 C 2/N.m2 e = Permittivity of material between plates A = Surface Area of one of the plates (SI: m 2) d = Separation of the plates (SI: m) =>A=1.524*10^-2 m^2 2)electric field strength=Q/Ae= 3*10^6 V/m =>Q=1.524*10^-2 m^2* 3*10^6 V/m*8.854x10-12 C 2/N.m2=0.405*10^-6 C V=Q/C=450V

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