An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnit

Question

An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnitude of charge on each plate is 0.0180 C when the potential difference is 200 V. Part A What is the capacitance? C = 9•107 F SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part B What is the area of each plate? A = 152.68 m2 SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part C What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric field strength of 3.0×106V/m.) Express your answer using two significant figures. Vmax = 450 V SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part D When the charge is 0.0180 C, what total energy is stored?

Explanation / Answer

step;1

now we find the capacitance

capacitance C=18*10^-9/200=9*10^-11 F

step;2

now we find the area of the each plate

capacitance C=8.85*10^-12*A/d

9*10^-11*1.5*10^-3=8.85*10^-12*A

area A=1.53*10^-2 m^2

step;3

now we find the maximum voltage

the maximum voltage Vmax=3*10^6*1.5*10^-3=4500 v

step;4

now we find the energy stored

the energy stored U=1/2*(18*10^-9)^2/9*10^-11=1*10^-7 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.