please solve this: A block with the mass m=3.20kg slides from laying still in a

Question

please solve this:

A block with the mass m=3.20kg slides from laying still in a length d down a frictionless inclined plane and hits a spring. The inclined plane has the angle theta = 30.0* with the horizontal.

The spring has the forceconstant k = 431 N/m.

The block will be momentarily still when the spring is compressed with 21.0cm.

a) Determine the length d.

b) What is the distance between the point of contact between block and spring and the point where the block has its maximum velocity?

Please help!

Explanation / Answer

p.e = 3.20*9.8*dcos30

sprimg energy = 1/2*k*x^2

so d = 0.3499 m

= 34.99 cm

b.) = d-21cm

= 13.99 cm

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