A long vertical wire carries a steady 13 A current. A pair of rails are horizont

Question

A long vertical wire carries a steady 13 A current. A pair of rails are horizontal and are 0.3 m apart. A 17.6 ? resistor connects points a and b, at the end of the rails. A bar is in contact with the rails, and is moved by an external force with a constant velocity of 0.6 m/s as shown. The bar and the rails have negligible resistance. At a given instant t1, the bar is 0.12 m from the wire, as shown. In Figure, at time t1, the induced current in A is:

A long vertical wire carries a steady 13 A current. A pair of rails are horizontal and are 0.3 m apart. A 17.6 ? resistor connects points a and b, at the end of the rails. A bar is in contact with the rails, and is moved by an external force with a constant velocity of 0.6 m/s as shown. The bar and the rails have negligible resistance. At a given instant t1, the bar is 0.12 m from the wire, as shown. In Figure, at time t1, the induced current in A is:

Explanation / Answer

Lets say distance from Connecting rod to wird d = x m

Then Area of Flux = 0.3*x m2

Magnetic field due to Wire = I/2x

Flux = = x2 I*dx/2x

=> = *13/2 *ln(2/x)

E = - d/dt = - d/dx*dx/dt = - (- *13/2 *2/x*1/2*0.6)

at x = 0.12

E = 1.3*10-6 V

So current = E/R = 0.074 A

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