A rocket, initially at rest on the ground, accelerates straight upward from rest

Question

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 29.4 m/s^2 . The acceleration period lasts for time 5.00s until the fuel is exhausted. After that, the rocket is in free fall.

Find the maximum height(y max)reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to9.80m/s^2

Explanation / Answer

a1 : acceleration before fuel ending a2 : acceleration after fuel ending V2 : initial velocity for second movement ----------------------------- 1st movement is before the fuel finishes the height that rocket travels in 1st movement can be drove by: H1= 1/2 * a1 * t^2 + V1 * t V1 = 0 --> so H1=1960 ------------------------ V3^2 - V2^2 = 2*a2*H2 V3=0 because the rocket stops moving V2 = a1*t ---> V2=392 a2= -9.8 153664=192.08*H2 H2=800 ---------- H=H1+H2----------> H=2760 ---------- Its finished but try to solve your class questions yourself My Friend ;D!

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