A rocket of mass 2 kg accelerates upward at a constant 5 g\'s for 5 seconds star
ID: 1998736 • Letter: A
Question
A rocket of mass 2 kg accelerates upward at a constant 5 g's for 5 seconds starting from rest. Assuming the mass of the fuel is negligible so the mass of the rocket can be considered constant throughout the acceleration. a) How much energy is imparted to the rocket during the first second? b) How much energy is imparted to the rocket during the last second? c) Is chemical energy that drives the rocket being expended at the same rate during the first second as during the last second? d) Explain why answers a and b are not the same. Where does the extra energy go? A rocket of mass 2 kg accelerates upward at a constant 5 g's for 5 seconds starting from rest. Assuming the mass of the fuel is negligible so the mass of the rocket can be considered constant throughout the acceleration. a) How much energy is imparted to the rocket during the first second? b) How much energy is imparted to the rocket during the last second? c) Is chemical energy that drives the rocket being expended at the same rate during the first second as during the last second? d) Explain why answers a and b are not the same. Where does the extra energy go? A rocket of mass 2 kg accelerates upward at a constant 5 g's for 5 seconds starting from rest. Assuming the mass of the fuel is negligible so the mass of the rocket can be considered constant throughout the acceleration. a) How much energy is imparted to the rocket during the first second? b) How much energy is imparted to the rocket during the last second? c) Is chemical energy that drives the rocket being expended at the same rate during the first second as during the last second? d) Explain why answers a and b are not the same. Where does the extra energy go?Explanation / Answer
a) energy imparted = change in kinetic energy = 5 mgh = 5*2*9.8*0.5*5*9.8*t^2
energy imparted in first second = 5*2*9.8*0.5*5*9.8*1^2
= 2401 J
b) energy imparted during last second =5*2*9.8*0.5*5*9.8*(5^2-4^2)
= 21609 J
c) no
d) Because kinetic energy change is greater in last second. The extra energy increases the speed.
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