A rocket is lauchened and travels vertically up. At a designated point, when it

Question

A rocket is lauchened and travels vertically up. At a designated point, when it travels at 500 m/s, two empty tanks, each of mass 1 t, are separated from the rocket. The velocity of tank 1 immediately after separation is vx = 20 m/s, vy = 450 m/s and the velocity of tank 2 is vx = 10 m/s, vy = 400 m/s. Here the y-direction is "up", and x is a horizontal direction. What are the components of the velocity of the remaining rocket, just after the tanks have separated, if the mass of the remaining rocket is 5 t? Assume that you can neglect gravity during the separation.

A. vx = 6 m/s, vy = 530 m/s

B. vx = - 6 m/s, vy = 530 m/s

C. vx = -30 m/s, vy = 480 m/s

D. vx = 30 m/s, vy = 480 m/s

Explanation / Answer

    option A i s correct one

rocket is launched vetically up so the x component of velocity of the rocket is zero

now conservation of momentum of x component and y component

momentum x componet is 7t (0) = (20+10)t - 5t *vx
                                  Vx= 6 m/s
momentum y component 7t*500 = (450+400)t -5t vy
                            vy = 530 m/s

so A. vx = 6 m/s, vy = 530 m/s is correct option

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