The helicopter view in the figure below shows two people pulling on a stubborn m
ID: 2172170 • Letter: T
Question
The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F1 = 134 N and F2 = 85.0 N.) (a) Find the single force that is equivalent to the two forces shown above. magnitude Incorrect: Your answer is incorrect. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N direction Incorrect: Your answer is incorrect. Your response differs from the correct answer by more than 10%. Double check your calculations.? (counterclockwise from the +x-axis) (b) Find the force that a third person would have to exert on the mule to make the net force equal to zero. magnitude Incorrect: Your answer is incorrect. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N direction Incorrect: Your answer is incorrect. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.? (counterclockwise from the +x-axis)
Explanation / Answer
I'm assuming that the 125N force is pulling at 60o above the x axis and the 85N force is at 75o below the x axis. If this is wrong please re-post this info So using components F1x = F18cos(60) = 125N*cos(60) = 62.5N F1y = f1*sin(60) = 125N*sin(60) = 108.3 For F2 we have F2x = 85*cos(-75) = 22.0N and F2Y = 85N*sin(-75) = -82.1 So Fx = F1x + F2x = 62.5 + 22 = 84.5N and Fy = 108.3 - 82.1 = 26.2N So F = sqrt(84.5^2 + 26.2^2) = 88.5N and ? = arctan(Fy/Fx) = arctan(26.2/84.5) = 17.2o b) To make the net force zero a third person would pull with a force = 88.5N and at an angle od 17.2+180 = 197.2o
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