a. What is the minimum area of the top surface of a slab of ice 0.30 m thick flo

Question

a. What is the minimum area of the top surface of a slab of ice 0.30 m thick floating on fresh water that will hold up an automobile of mass 1100kg?

b. Does it matter where the car is placed on the block of ice? (density of ice = 917 kg/m3)

Please, help! Im lost in this question, please can you explain in detail? thanks!

Explanation / Answer

Mass of slab of ice =0.30*A*917 Buoyant force = 0.30*A*1000*g [taking density of water =1000kg/^3] now (0.3*A*917+1100)*g= 0.3*A*1000*g 1100=24.9*A =>A=44.176 m^2 (min area) Yes it matters where the car is placed on Ice Slab because center of mass of the system will shift if car is not placed in the center which will create a torque of force and car can sink into water

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