A block of mass m1 = 4.1 kg rests on a frictionless horizontal surface. A second

Question

A block of mass m1 = 4.1 kg rests on a frictionless horizontal surface. A second block of mass m2 = 2.5 kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block. The blocks are released from rest.
(a) Find the acceleration of the two blocks after they are released.
block 1: magnitude



block 2: magnitude




(b) What is the velocity of the first block 2.0 s after the release of the blocks, assuming the first block does not run out of room on the table and the second block does not land on the floor?
magnitude

m/s
direction


(c) How far has block 1 moved during the 2.0-s interval?
m

(d) What is the displacement of the blocks from their initial positions 0.10 s after they are released?
block 1: magnitude

m
direction


block 2: magnitude

m
direction

Explanation / Answer

a) a = g/[1+(m1/m2)] = 3.7121m/s² b) v = a*t = 3.7121m*2 = 7.42 m/s horizontally c) x = ½a*t² = .5*3.712*2² = 7.42 m d) disp = ½a*t² = .5*3.712*.10² = .0186 m; block 1 move horizontally. block 2 moves downward

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