35. In a surprise assignment, you are in charge of explaining to your lab partne

Question

35. In a surprise assignment, you are in charge of explaining to your lab partners how a catalyst contributes to accelerate the rate of a reaction. Your lab instructor provides you with a large illustration that looks like the graph on the right. You may start by establishing what X and Y are; what the difference b-d represents and what do a, b, c, and d mean. a) b) c) d) t (millisec) 36. The enzyme E can bind to two different substrates, S and I. The binding reactions are described by the following equations and values: E+S ES K for ES- 10 E+I E K for El- 2 a) Based on the equilibrium constant values, which one of the following statements is true? b) E binds I more tightly than S c) When S is present in excess, no I molecules will bind to E d) The binding energy of the ES interaction is greater than that of the El interaction. e) Changing an amino acid on the binding surface of I from a basic amino acid to an acidic one will likely make the free energy of association with E more negative. B C+D, K ICIDIAIB] Remember that for the reaction A 37. The following statement about Km is incorrect. a) In a double reciprocal plot, the ordinate axis intercept is equal to 1/Km. c) The larger an enzyme's Km for a certain substrate A the lower the affinity for A d) Km has units of concentration (e.g., mM. uM, nm, etc.)

Explanation / Answer

35. This is the graph of activation energy requirements of ctalayzed and non catalyzed enzyme reaction. Here,  

a. show substrate

b .show activation energy without enzyme

c show activation energy with enzyme

d. Products

36. In this question, since km value for second reaction is more, hence more binding energy is released. Hence, option d is correct

37. Intercept is equal to 1/ vmax. Hence, option a is incorrect.

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