OK, I already have the answer for the first part of the question, which is 5m, I

Question

OK, I already have the answer for the first part of the question, which is 5m, I understand how to get that, the second part of the question "You found the distance that you will cover while braking. You can use the expected amount of time for braking to check your answer for distance.
Using the information given in the introduction and the value for distance that you found above, determine the time required for you to stop once you press the brakes. Note that the time for braking is just the time interval . PUT THIS IN SECONDS"

Here is the first part, where the answer 5m came from: You are driving down the highway late one night at 20 when a deer steps onto the road 35 in front of you. Your reaction time before stepping on the brakes is 0.50 , and the maximum deceleration of your car is 10 . How much distance is between you and the deer when you come to a stop?

Please help with the second part of the question about time required to stop once the brakes were applied. Thank you!

Explanation / Answer

distance traveled in 0.50 s = 20 X 0.50 = 10 m Now, distance traveled during deceleration = 20^2/(2 X 10) = 20 m (v^2 = u^2-2as; here, v = 0, u = 20 m/s, a = 10 m/s^2) (checkout: http://en.wikipedia.org/wiki/Acceleratio… So, total distance traveled = 10 + 20 = 30 m Ans:35-30 = 5 m Similar Problem: distance traveled in 0.50 s = 20 X 0.50 = 10 m distance traveled during deceleration = 20^2/(2 X 6.0) = 33.33 m total distance traveled = 43.33 m So, collision can be avoided.

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