A proton is placed at the origin. An electron that is initially very far away is

Question

A proton is placed at the origin. An electron that is initially very far away is then taken on the path shown in the figure below and eventually stops a distance of d = 4.4 nm (= 4.4x10-9 m) from the proton. How much work was done on the electron to move it along this path?

Explanation / Answer

(a) electron mass = 9.10938188 × 10-31 kilograms (Refer to the link below.) As the electron moves on a circular path, the force due to the magnetic field acting on it is centripetal and hence perpendicular to the velocity of the electron. => mv^2 / r = Bvq => v = Bqr/m = (3.6x10^-4) * (1.6x10^-19) * (0.037) / (9.10938188 × 10-31) = 1.46 x 10^6 m/s. (b) Same as above. (c) Zero. As the magnetic force is perpendicular to the direction of velocity of the electron, no work is done by it on the electron

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