A proton is between two oppositely charged plates that produce a constant electr

Question

A proton is between two oppositely charged plates that produce a constant electric field. The region between the plates is a vacuum. a. The proton accelerates downward. The proton accelerates upward. The proton moves with constant velocity downward. The proton moves with constant velocity upward. The proton does not move. In the problem above what happens to the electric potential energy of the proton as it moves? a. It remains constant because it is a uniform electric field. It will increase because the charge moves in the same direction as the E-field. It will decrease because the charge moves in a direction opposite the E-field. It will increase because the charge moves in a direction opposite the E-field. It will decrease because the charge moves in the direction of the E-field. A positive charge may be placed at either position a or b in a uniform electric field. The force at position a is greater than at position The force at position a is less than at posi

Explanation / Answer

23)

as proton is having positive charge

that tha value of = 1.6 X 10-19 C

mass = 1.67 X 10-27 kg

here the proton is trapped in between two oppositely charged plates

soo here in this case the proton does not move in any other direction

beacuse it creates a constant electric field.

So Option " e " is correct

24 )

same considering as above explanation

it creates a constant electric field

So " it remains constant beacuse it is a uniform electric field "

So option " a " is correct

25 )

Option " d " is correct

that the force is same but not zero

beacuse positive charge is having and affecting some force.

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