A student stands at the edge of a cliff and throws a stone horizontally over the

Question

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of13.0m/s. The cliff ish=71.0m above a flat, horizontal beach as shown in the figure.

(a) What are the coordinates of the initial position of the stone?

x0 = m

y0 = m

(b) What are the components of the initial velocity?

v0x = m/s

v0y = m/s

(c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)

vx =

vy =

(d) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)

x =

y =

(e) How long after being released does the stone strike the beach below the cliff?

s =

(f) With what speed and angle of impact does the stone land?

vf = m/s

? = ? below the horizontal

Explanation / Answer

a) x0 = 0m y0 = 71m b) v0x = 13 m/s v0y = 0m/s c) vx = v0x = 13 vy = 0+gt =9.8t d) x = v0x x t =13t y=0.5gt^2 = 4.9xt^2 e)s= 49.485 m f)vf = 39.5 m/s 70.78 degrees below horizontal

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