A student standing at the edge of a 40.0 m high cliff threw a stone horizontally

Question

A student standing at the edge of a 40.0 m high cliff threw a stone horizontally and it hit the ground 60.0 meters from the base of the cliff. (Include a labeled diagram showing this information.)
a) How long after its release did the stone hit the ground? (Include any formulas/equations used, show your substitution into any formula/equation used, and show the answer resulting from your substitution into any formula/equation used.)
b) Calculate the stone’s initial velocity. (Include any formulas/equations used, show your substitution into any formula/equation used, and show the answer resulting from your substitution into any formula/equation used.)
c) How high was the cliff? (Include any formulas/equations used, show your substitution into any formula/equation used, and show the answer resulting from your substitution into any formula/equation used.)
d) Calculate the stone’s vertical velocity just before it hit the ground. (Include any
formulas/equations used, show your substitution into any formula/equation used, and
show the answer resulting from your substitution into any formula/equation used.)
e) Calculate the stone’s velocity just before it hit the ground. (Include a labeled diagram showing the individual velocity vectors, and the resulting velocity vectors.)
f) What was the stone’s speed just before it hit the ground?

Explanation / Answer

a) (40*2/9.8)=2.86 s

b) x=vox*t vo=vox=60/2.86=21 m/s

c) cliff was 40 m high, result was given in question

d) vyfinal=voy+g*t=9.8*2.86=28 m/s

e) v=(21²+28²)=35 m/s

f) 35 m/s

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