b.) What is the direction of the electric field at the ball?s location due to th

Question

b.)

What is the direction of the electric field at
the ball?s location due to the charged wall,
relative to the given coordinate axes?

1. Directed along the positive x-axis.
2. Directed along the positive y-axis.
3. Directed downward and to the right,
along the line of the thread.
4. Directed along the negative y-axis.
5. Directed upward and to the left, along the
line of the thread.
6. Directed along the negative x-axis.

c.)

Find the perpendicular distance from the wall
to the center of the ball.
Answer in units of m

Any help is appreciated!!!

A wall has a negative charge distribution producing a uniform horizontal electric field. A small plastic hail of mass 0.0285 kg, carrying charge of -108 muC, is suspended by an uncharged, nonconducting thread 0.264 m long. The thread is attached to the wall and the hail hangs in equilibrium in the electric and gravitational fields, as shown. Find the magnitude of the electric field at the ball's location due to the charged wall. Assume the electric force on the ball has a magnitude of 0.0578 N. The acceleration due to gravity is 9.8 m/s^2. Answer in units of N/C

Explanation / Answer

angle os suspension is tan = F/mg

                                             = 0.0578/0.0285*9.8

                                       = tan^-1(0.206) = 11.7 deg

sin = opp/hypo

opp side = hypo* sin 11.7 deg

              = 0.264* 0.202

             = 0.0535 m

E at a 0.0535 m = kQ/r^2 = 9*10^9*106*10^-6/0.0535^2

                   = -3.33 *10^8 N/C

B)Directed along the negative x-axis.

c)

angle os suspension is tan = F/mg

                                             = 0.0578/0.0285*9.8

                                       = tan^-1(0.206) = 11.7 deg

sin = opp/hypo

opp side = hypo* sin 11.7 deg

              = 0.264* 0.202

             = 0.0535 m

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