A single conservative force acting on a particle varies as F = (-Ax + Bx4)i N, w

Question

A single conservative force acting on a particle varies as F = (-Ax + Bx4)i N, where A and B are constants and x is in meters.
(a) Calculate the potential energy function U(x) associated with this force, taking U = 0 at x = 0. (Use A, B, and x as appropriate.)
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(b) Find the change in potential energy and change in kinetic energy as the particle moves from x = 2.00 m to x = 3.80 m. (Use A, B, and x as appropriate.)
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?K = Click here to preview your answer.

Explanation / Answer

(a) PE = integ(F dx) = -Ax^2/2 +Bx^5/5 (b) change in PE = -A (3.8^2 -2^2)/2 + B (3.8^5 - 2^5)/5 = -5.22A+152B (A and B are not given )

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