A ball starts from rest and accelerates at 0.500 m/s2 while moving down an incli

Question

A ball starts from rest and accelerates at 0.500 m/s2 while moving down an inclined plane 9.00 m long. When it reaches the bottom, the ball rolls up another plane, where, after moving 15.0 m, it comes to rest. (a) What is the speed of the ball at the bottom of the first plane? (b) How long does it take to roll down the first plane? (c) What is the acceleration along the second plane? (d) What is the ball's speed 8.00 m along the second plane?

Explanation / Answer

a) v^2 = vo^2 + 2 *a * d = 0 + 2 * 0.5 * 9 v = 3 m/s (it is the speed of the ball at the bottom of the first plane ) (b) v = vo + a * t 3 = 0 + 0.5 t ---> t = 6 s (c) v^2 = vo^2 + 2 *a * d 0 = 3^2 + 2 * a * 15 0 = 9 + 30a ---> a = -9/30 = -0.3 m/s^2 (d) v^2 = vo^2 + 2 *a * d = 3^2 + 2 * (-0.3) * 8 = 4.2 --> v = 2.05 m/s

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