A rotating merry-go-round makes one complete revolution in 4.0 s. (a) What is th

Question

A rotating merry-go-round makes one complete revolution in 4.0 s. (a) What is the linear speed of a child seated 1.2 m from the center? (b) What is her acceleration (given components)?

Explanation / Answer

> linear speed of a child seated 1.1 m from the center? linear speed = distance / time She's going in a circle. So, during one revolution, the distance she travels is just the circumference of that circle. The radius of the circle is 1.1 meters; so its circumference is: C = 2p(1.1 meters) so: Linear speed = C / 4.2s > What is her acceleration... The formula for centripetal (radial) acceleration is: A_c = (linar speed)² / r You calculated linear speed above; and "r" is of course 1.1 meters. The formula for tangential acceleration is: A_t = (change in linear speed) / t

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