An unsuspecting bird is coasting along in an easterly direction at 3.00 mph when

Question

An unsuspecting bird is coasting along in an easterly direction at 3.00 mph when a strong wind from the south imparts a constant acceleration of 0.400 m/s2. If the acceleration from the wind lasts for 2.60 s, find the magnitude, r, and direction, ?, of the bird's displacement during this time period. (HINT: assume the bird is originally travelling in the x direction and there are 1609 m in 1 mile.)

r= _______ meters
theta= ________degrees

Now, assume the same bird is moving along again at 3.00 mph in an easterly direction but this time the acceleration given by the wind is at a 32.0 degree angle to the original direction of motion. If the magnitude of the acceleration is 0.500 m/s2, find the displacement vector , and the angle of the displacement, ?1. Enter the components of the vector and angle below. (Assume the time interval is still 2.60 s.)

r= ________ meters i + ________ meters j
theta1=__________degrees

Explanation / Answer

Vb = 1.34 i meter/sec Aw = -0.4 j m/s^2 x component of bird = 1.34 * 2.6 = 3.484 i y component of bird = - 0.5 *0.4* 2.6*2.6 = -1.352 j displacement = 3.484 i - 1.352 j magnitude = 3.737 meters angel = 338.79 degrees with + x axis in anti clock wise direction 2ND CASE Vb = 1.34 i meter/sec in this case two cases arised it makes 32 degrees ,but this may be in anticlock wise or clock wise so please specify that condition

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