) A projectile is fired from ground level at time , at an angle with respect to

Question

) A projectile is fired from ground level at time , at an angle with respect to the horizontal. It has an initial speed . In this problem we are assuming that the ground is level. A)Find the time it takes the projectile to reach its maximum height . B) Find , the time at which the projectile hits the ground after having traveled through a horizontal distance . C)Find , the maximum height attained by the projectile. D)Find the total distance (often called the range) traveled in the x direction; see the figure in the problem introduction.

Explanation / Answer

A) Vy = Uy - gt Vo sin(theta) = gt t = Vo sin(theta) / g B) Total time = 2* time taken to reach maximum height = 2 * Vo sin(theta) /g C) maximum height Vy^2 = Uy^2 - 2gS S = Vo^2 (sin(theta) )^2/ (2g) D) range S = Uxt = Vo cos(theta) * 2 * Vo sin(theta) /g = Vo sin(2 theta) /g

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