(you missed GGA, Please cross check) Sequences of single strands of DNA are show
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Question
(you missed GGA, Please cross check)
Sequences of single strands of DNA are shown below for two different pieces of DNA. Assume that the DNA sequences are not at the beginning of a gene and that the spaces between each DNA triplet represent the correct reading frame. Label all sequences 5’ and 3’, where appropriate. Keep everything aligned properly.
Synthesize the complementary DNA sequence.
B. Transcribe the mRNA sequence starting with the 5’ end on the left-hand side.
C. Write the complementary tRNA sequence for each reading frame.
D. Use the genetic code table from our lecture notes or from our textbook (Bauman, 4th ed., p. 208; Bauman, 3rd ed, p. 209; Bauman, 2nd ed., p. 211) to translate the amino acid sequence of the encoded polypeptide, using the three-letter code for each amino acid. Note: Use only the 20 amino acids that are most commonly found in all living organisms.
3’ 5’
1. CCC GAC TCA CTT TAG CCG TTA TAG GGA AAA ATC
A.
B.
C.
D.
5’ 3’
2. GGT GCG CAC ATT TAC AAA GTT AAC CTC CAG GTA
A.
B.
C.
D.
(micro biology assignment)
Explanation / Answer
1. Considering the sequence from 5' to 3', the order is as follows:
5' CTA AAA AGG GAT ATT GCC GAT TTC ACT CAG CCC 3'
A. The complementary DNA strand is:
3' GAT TTT TCC CTA TAA CGG CTA AAG TGA GTC GGG 5'
B. The mRNA sequence is:
5' CUA AAA AGG GAU AUU GCC GAU UUC ACU CAG CCC 3'
C. The complementary tRNA sequence is:
3' GAU 5' ; 3' UUU 5' ; 3' UCC 5' ; 3' CUA 5' ; 3' UAA 5' ; 3' CGG 5' ; 3' CUA 5' ; 3' AAG 5' ; 3' UGA 5' ; 3'GUC5' ;
3' GGG 5'.
D. If we arrange tRNAs in 5' to 3' direction, then the alignment will be like this:
GGG CUG AGU GAA AUC GGC AAU AUC CCU UUU UAG ( reverse of 3' to 5' direction ).
So, the sequence of amino acids is:
Gly-Leu-Ser-Glu-Ile-Gly-Asn-Ile-Pro-Phe-stop signal (UAG).
All the four parts of 1st question has been done, similarly 2nd queation is to be done.
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