Three digital clocks A, B, and C run at different rates and do not have simultan

Question

Three digital clocks A, B, and C run at different rates and do not have simultaneous readings of zero. The figure shows simultaneous readings on pairs of the clocks for four occasions. (At the earliest occasion, for example, B reads 25.0 s and C reads 92.0 s.) If two events are 1100 s apart on clock A, how far apart are they on (a) clock B and (b) clock C? (c) When clock A reads 400 s, what does clock B read? (d) When clock C reads 21 s, what does clock B read? (Assume negative readings for prezero times.)

I have part a and part b already.

a) 907.5 s

b)259.2857142857143 S

Need C and D

Explanation / Answer

50 in clock C = 125 in clock B and 165 in clock B = 200 in clock A C) 400 = 312 + 88 ==> 88 equalent in B = 88*165/200 = 72.6 ==> clock B reads 125 + 72.6 = 197.6 D) 21 = 92 - 71 ==> 71 equalent in B = 71*125/50 = 177.5 ==> clock B reads 25 - 177.5 = -152.5

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