velocity vi = (4.00 i(hat) + 1.00 j(hat) ) m/s at a point in the ocean where the

Question

velocity vi = (4.00 i(hat) + 1.00 j(hat) ) m/s at a point in the ocean where the position relative to a certain rock is ri = (12.0 i(hat) - 3.00 j(hat) ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is v = (19.0 i(hat) - 1.00 j(hat) ) m/s.

(a) What are the components of the acceleration of the fish?
ax = ??? m/s2
ay = ??? m/s2

(b) What is the direction of its acceleration with respect to unit vector i(hat)?
__________ degree counterclockwise from the +x-axis

(c) If the fish maintains constant acceleration, where is it at t=28.0 s?
x = ??? m
y = ??? m

In what direction is it moving?
____________ degree counterclockwise from the +x-axis

Explanation / Answer

a)

ax = vx/t = (19-4)/17 = 0.8824m/s2

ay = vy/t = -1-1/17 = -0.1176m/s2

b)

direction of acceleration

tan = ay/ax = -7.5

therefore = -82.4 degree

c)

Final position

x = xi + vixt + 0.5axt2

and you can calculate it further.

Related Questions

Navigate

• Browse (All)
• Browse V
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.