A physics book slides off a horizontal tabletop with a speed of 1.10 . It strike

Question

A physics book slides off a horizontal tabletop with a speed of 1.10 . It strikes the floor in 0.350 . Ignore air resistance.

Q: Find the height of the tabletop above the floor.

Q: Find the horizontal distance from the edge of the table to the point where the book strikes the floor.

Q: Find the horizontal component of the book's velocity, just before the book reaches the floor.

Q: Find the vertical component of the book's velocity just before the book reaches the floor.

Q: Find the magnitude of book's velocity, just before the book reaches the floor.

Q: Find the direction of book's velocity, just before the book reaches the floor.


Please include how you came to get these answers too if possible. THANK YOU!

Explanation / Answer

For the first part, assuming there is no initial vertical velocity (which in this case, there is not), T = sq. rt. (2h/g) where T is time, h is the vertical height that it falls, and g is the acceleration due to gravity. 0.350 = sq. rt. (2h/9.8) .1223 = 2h/9.8 2h = 1.2005 h = about .6 meters d = v t where d = distance, v = velocity, and t = time. d= (1.10)(0.350) = 0.385 meters

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