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A physics book slides off a horizontal tabletop with a speed of 1.10m/s . It str

ID: 1269321 • Letter: A

Question

A physics book slides off a horizontal tabletop with a speed of 1.10m/s . It strikes the floor in 0.350s . Ignore air resistance.

Part A

Find the height of the tabletop above the floor.

Part B

Find the horizontal distance from the edge of the table to the point where the book strikes the floor.

Part C

Find the horizontal component of the book's velocity, just before the book reaches the floor.

Part D

Find the vertical component of the book's velocity just before the book reaches the floo

Part E

Find the magnitude of book's velocity, just before the book reaches the floor.

Explanation / Answer

A) h = 0.5*g*t^2

= 0.5*9.8*0.35^2

= 0.6 m

B) x = vx*t

= 1.1*0.35

= 0.385 m

C) vx = vox = 1.1 m/s

D) vy = sqrt(2*g*h)

= sqrt(2*9.8*0.6)

= 3.43 m/s

E) v = sqrt(vx^2 +vy^2)

= sqrt(1.1^2 + 3.43^2)

= 3.6 m/s

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