PLEASE ANSWER CLEARLY AND STEP BY STEP! and correctly Consider three (3) regions
ID: 2159911 • Letter: P
Question
PLEASE ANSWER CLEARLY AND STEP BY STEP! and correctlyConsider three (3) regions along the x-axis: (i) left of the -10uC charge, (ii) between the -10uC and +20uC charges, and (iii) right of the +20uC charge. Identify any region(s), other than infinity, in which it is possible for the net electric field to be zero. Also identify any region(s), other than infinity, in which it is possible for the net electric potential to be zero. Justify your answers QUALITATIVELY. no calculations.
ANSWERS:
(i) in this region the electric field can be zero because the charges cancel out. also it is possible for electric potential to be zero because it is closer to the smaller charges
MY QUESTION: *WHY DO THE CHARgES CANCEL OUT, AND WHAT DOES SMALLER CHARgE AFFECT ELECTRIC POTENTIAL?
(ii) in this region the electric field cannot be zero because the charges go in the same direction. however, the electric potential can be zero if the charge is closer to the small end (aka -10uC).
MY QUESTION: *HOW DO YOU DETERMINE THE DIRECTION OF THE CHARgES? WHY DOES THE ELECTRIC POTTENTICAL CAN BE ZERO IF CLOSER TO THE SMALLER CHARgE?
(iii) in this region, though the charges go in opposite directions, the magnitude of +20uC is large enough that the charges will not cancel. thus the electric field cannot be zero. also the electric potential cannot be zero in this region because V = k(q/r) formula.
MY QUESTION: *WHY DOES THE +20uC charge's large magnitude not allow the electric field to be zero?HOW IS THIS RELATED TO THE FORMULA V = k(q/r) ?????
Explanation / Answer
(i) left of the -10uC charge (i) left of the -10uC charge the potential depend on charge directly and distance inversely for the potential to cancel each other potential due to positive charge must be equal to that of a negative charge. so kq1/r1=kq2/r2 if q1>q2, r1>r2 also same logic is applied regarding elecric field
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