Figure 27-30 shows a resistor of resistance R = 6.01 ? connected to an ideal bat

Question

Figure 27-30 shows a resistor of resistance R = 6.01 ? connected to an ideal battery of emf = 13.7 V by means of two copper wires. Each wire has length 22.4 cm and radius 4.00 mm. In dealing with such circuits in this chapter, we generally neglect the potential differences along the wires and the transfer of energy to thermal energy in them. Check the validity of this neglect for the circuit of the figure below. What is the potential difference across (a) the resistor and (b) each of the two sections of wire? At what rate is energy lost to thermal energy in (c) the resistor and (d) each section of wire?

Explanation / Answer

you need to know the ressitivity value of copper first which is not given get from net R = resistivity * length /Area calculate current = v/r+R : potential diff acrros resistance = i*R which ever resistnace you want to know energy dissipated = i*i Rt

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