At launch the space shuttle weighs 4.5 million pounds. When it is launched from

Question

At launch the space shuttle weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 to reach 157km/h , and at the end of the first 1.00min its speed is 1570km/h. What is the average acceleration (in m/s^2) of the shuttle between 8.00s and the end of the first 1.00min ? Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the shuttle travel during the first 8.00s ? and what distance does the shuttle travel during the interval from 8.00 to 1.00min ?

Explanation / Answer

First we need to cobvert to meters per second

157 km/hr = 43.61 m/s

1570 km/hr = 436.1 m/s

The acceleration between 0 sand 8 sec is found by

vf = vo + at

(43.61) = (0) + a(8)

a = 5.45 m/s2

The acceleration between 8 sec and 1 min is...

vf = vo + at

436.1 = 43.61 + a(52)

a = 7.55 m/s2

The distance for the first 8 sec is found by

d = vot + .5at2

d = (0) + .5(5.45)(8)2

d = 174.4 m

The distance between 8 sec and 1 min is

d = vot + .5at2

d = (43.61)(52) + (.5)(7.55)(52)2

d = 12475.32 m   which is 1.25 X 104 m

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