Two blocks are free to move on a horizontal frictionless surface. Block A has a

Question

Two blocks are free to move on a horizontal frictionless surface. Block A has a mass m = 2kg and is initially moving to the right with a speed of v = 5m/s. Block B has a mass of m = 6kg and is initially not moving.

1) If the blocks collide and stick together, what is the final velocity of the two blocks?

vf = 1.25 m/s
vf = 1.75 m/s
vf = 2.00 m/s

2) If two blocks collide elastically (bounce off) what is the final velocity of block A?

v = 2.0 m/s to the left
v = 2.5 m/s to the left
v = 2.0 m/s to the right
v = 2.5 m/s to the right

3) If two blocks collide elastically (bounce off) what is the final velocity of block B

v = 2.0 m/s to the left
v = 2.5 m/s to the left
v = 2.0 m/s to the right
v = 2.5 m/s to the right

with brief explanation(or formula) please?

Explanation / Answer

1) 2*5+0 =(2+6)*Vf hence Vf =1.25 2) VfA =[(2-6)*5+2*6*0]/(2+6) =-2.5 ie 2.5 to the left 3)Vfb =[(6-2)*0+2*2*5]/(2+6) =2.5 ie t2.5 to the right

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