A golf ball strikes a hard, smooth floor at an angle of 28.9 A golf ball strikes

Question

A golf ball strikes a hard, smooth floor at an angle of 28.9

A golf ball strikes a hard, smooth floor at an angle of 28.9 degree and, as the drawing shows, rebounds at the same angle. The mass of the ball is 0.0258 kg, and its speed is 51.9 m/s just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? (Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.)

Explanation / Answer

Vv = 51.9m/s * cos28.9

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