A 1 = 2.80 capacitor is charged to 858 V and a 2 = 6.80 capacitor is charged to

Question

A 1 = 2.80 capacitor is charged to 858 V and a 2 = 6.80 capacitor is charged to 642V . These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other.







Part A

What will be the potential difference across each? [Hint: charge is conserved.]

Enter your answers numerically separated by a comma.


I have part a








Part B

What will be the charge on each?

Enter your answers numerically separated by a comma.


Need Help with this!!!!!! Part B

Explanation / Answer

potential differene across them will be same after they are connected to each other initial charges Q1 = 2.8*858 = 2402.4 Q2 =4365.6 Final charge = C1V + C2V = 4365.6 + 2402.4 V = 705 V charge on first capacitor plates = C1V = 1974 C charge on second capacitor = C2V = 4794

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