A 1 480-kg automobile has a wheel base (the distance between the axles) of 3.10

Question

A 1 480-kg automobile has a wheel base (the distance between the axles) of 3.10 m. The automobile's center of mass is on the centerline at a point 1.25 m behind the front axle. Find the force exerted by the ground on each wheel.

each front wheel
The net torque on the car is zero. Think carefully about what point to use for the center of rotation. kN each rear wheel kN A 1 480-kg automobile has a wheel base (the distance between the axles) of 3.10 m. The automobile's center of mass is on the centerline at a point 1.25 m behind the front axle. Find the force exerted by the ground on each wheel. each front wheel The net torque on the car is zero. Think carefully about what point to use for the center of rotation. kN each rear wheel kN

Explanation / Answer

the force exerted vy the ground on each wheel

data:

mass= 1480 kg

Distance axles=3.1 m

centerline= 1.25 m

firts we calculated the weight

W= m.g

W=1480 kg * 9.8 m)s2= 14504 N = 14.504 kN

then the force is calculated for each wheel:

the front axle

Distance axles * force = (Distnces axles - centerline)* W

2.9 * F1= (2.9 - 1.25)* 14504 N -----> F1= 8252.26 N = 8,25 kN

an axles have 2 wheels, we divide by 2 ----> F1/2= 4126.13 N = 4.126 kN

the rear axle

distance acles * F= centerline * W

2.9 * F2 = 1.25 * 14504 N -----> F2= 6251.72 N = 6.25 kN

we divide by 2: F2/2= 3125.86 N = 3.125 kN

in the front axles each wheel have a force of 4.126 kN and in the rear axle the force by each wheel is 3.125 kN

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