Tries 0/10 A block of mass 0.64kg starts from rest at point A and slides down a

Question

Tries 0/10 A block of mass 0.64kg starts from rest at point A and slides down a frictionless hill of height h. At the bottom of the hill it slides across a horizontal piece of track where the coefficient of kinetic friction is 0.43. This section (from points B to C) is 4.27m in length. The block then enters a frictionless loop of radius r= 3.73m. Point D is the highest point in the loop. The loop has a total height of 2r. Note that the drawing below is not to scale. What is the minimum speed of the block at point D that still allows the block to complete the loop without leaving the track? What is the minimum kinetic energy for the block at point C in order to have enough speed at point D that the block will not leave the track? What is the minimum kinetic energy for the block at point B in order to have enough speed at point D that the block will not leave the track?

Explanation / Answer

I would work this backwards.
1. In order to "loop-the-loop", centripetal accel = g, or
9.8m/s

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