You are exploring a planet and drop a small rock from the edge of a cliff. In co

Question

You are exploring a planet and drop a small rock from the edge of a cliff. In coordinates where the +y direction is downward and neglecting air resistance, the vertical displacement of an object released from rest is given by y - y0 =(1/2)gplanett2, where gplanet is the acceleration due to gravity on the planet. You measure t in seconds for several values of y - y0 in meters and plot your data with t2 on the vertical axis and y - y0 on the horizontal axis. Your data is fit closely by a straight line that has slope 0.600 s2/m. Based on your data, what is the value of gplanet?

Explanation / Answer

formula for slopeof straight line =t^2/(y-yo)=0.6....

accelaration due to gravity is g planet= 2[(y-yo)/t^2]   = 2 * [t^2/(y-yo)]   =2/0.6=3.34m/s^2

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