Two concave mirrors face each other as shown. They are 19m apart. Use f1=4m and

ID: 2142306 • Letter: T

Question

Two concave mirrors face each other as shown. They are 19m apart. Use f1=4m and f2=3.5m. A 2m tall person is between the mirrors 5 from the right mirror. There will be an infinite number of images formed since light can keep bouncing back and forth but let us focus on one particular image. Start with light bouncing of the right mirror and then bouncing off the left mirror. Determine the location and height of that image. Solve this graphically and using the equations. Do not expect your graphical solution to perfectly match the mathematical one. Do not draw rays through C since they will not intersect very well.

(The answer is 2.22m to the left of the lens, 1.42m tall (inverted).....but I don't know how to get this answer....please help...help...help...thank you!!!!!!

Explanation / Answer

Before I begin, the answers you have listed are incorrect. You talk about a lens and here we have mirrors. I think the answers you typed in were for a different problem. For this problem here is the solution...

First solve for the right mirror by applying 1/f = 1/p + 1/q

1/3.5 = 1/5 + 1/q

q = 11.7 m

That means the image is 11.7 m in front of the right mirror.

Since the mirrors are 19 m apart, that image is 19 - 11.7 = 7.33 m from the left mirror

Again apply 1/f = 1/p + 1/q

1/4 = 1/7.33 + 1/q

q = 8.8 m

For the height, first find the magnification M

M = -q/p times -q/p

-11.7/5 times -8.8/7.33

M = 2.81

Finally M = h'/h

2.81 = h'/2

h' = 5.62 m

Navigate

Two concave lenses, each with f = -12 cm , are separated by 4.3 cm . An object i

Two concentration cells are prepared, both with 90.0 mL of 0.0100 M Cu(NO3)2 and

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

Two concave mirrors face each other as shown. They are 19m apart. Use f1=4m and

Question

Explanation / Answer

Related Questions

Navigate