A particular constant, horizontal force exerted on a particular object free to s

Question

A particular constant, horizontal force exerted on a particular object free to slide on a level, frictionless surface causes it to speed up with an acceleration of 0.5 g

A particular constant, horizontal force exerted on a particular object free to slide on a level, frictionless surface causes it to speed up with an acceleration of 0.5 g's. If the magnitude of the force is reduced to one-fourth of its original value, while the mass of the object is reduced to two-thirds of its original value, what is the new value of acceleration in units of m/s2?

Explanation / Answer

F = ma

F = m x0.5g

F/m = 0.5g

now , F' = F/4 and m' = 2m/3

so using F' = m'a'

F/4 = 2ma/3

a = (3/8)F/m   = 3/8 x 0.5g = 0.1875g   or 1.84 m/s2

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