The drawing shows a collision between two pucks on an air-hockey table. Puck A h
ID: 2141910 • Letter: T
Question
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.028 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.058 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the final speed of puck B.
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.028 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.058 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the final speed of puck B.Explanation / Answer
you find your term like this sulotion, your fig not clear.
Total momentum before collision = 0.033 x 5.5 + 0.063 x 0 = 0.1815 kg?m/s to the right
So total momentum after collision = 0.1815 kg?m/s to the right
let the final velocity of puck A = v(A)
and the final velocity of puck B = v(B)
Draw the momentum vector triangle:
Total momentum is 0.1815 kg?m/s horizontally to the right
Momentum of A is 0.033 v(A) at 65
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