a) The answer for radius is 7cm. I need b. I used E=k(z)(q)/(z^2+R^2)^(3/2) and

Question

a) The answer for radius is 7cm. I need b. I used E=k(z)(q)/(z^2+R^2)^(3/2) and isolated for q. The answer is supposed to be in nC. The electric field on the axis of a uniformly charged ring has magnitude 370kN/C at a point 5.8cmcm } from the ring center. The magnitude 18cm from the center is 120kN/C ; in both cases the field points away from the ring. Find the ring's radius...b)find the ring's charge. The answer for radius is 7cm. I need b. I used E=k(z)(q)/(z^2+R^2)^(3/2) and isolated for q. The answer is supposed to be in nC.

Explanation / Answer

E = kqx/(x^2+r^2)^1.5

so, 370*1000 = kq*0.058/(0.058^2+r^2)^1.5

Also, 120*1000 = kq*0.18/(0.18^2+r^2)^1.5

Here k = 9*10^9

Solving these two equations , we get

So, r = 0.0787 m = 7.01 cm <---------answer

q = 5.34*10^-7 C = 534 nC <--------answer

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