Problem 1 Two thin plates with area A = 5.0 cm2 are parallel to one another, sep

ID: 2141481 • Letter: P

Question

Problem 1 Two thin plates with area A = 5.0 cm2 are parallel to one another, separated

by a small gap d = 0.5 mm. A charge of 3.0 pC has been removed from one plate

and placed on the other. Assuming that the charge is uniformly distributed on

both plates, what is the strength of the electric field in the gap. What is the

electric field external to the plates? What is the force of attraction between the

two plates? (You may approximate the field as though the plates were infinite

sheets having the same uniform charge density.)

Problem 2.7. A charge of 1 nC is added to a spherical soap bubble with a radius of 3.0

cm. (a) What is the electric field strength just outside of the bubble? What is

the electric field strength just inside of the bubble? (b) The field experienced

by each charge in the skin of the bubble is the average of the field strength just

inside and the field just outside the bubble. Given this, what outward pressure

(in N/m2) is exerted on the bubble as a result of it being charged?

C = eo A/d

where C = capaciatance , A = area, d= distance beteen the plates

Q = CV , where V is Pot difference

also E = V/d -----------> V = Ed

then rearranging we can get Q = e0 EA

a. electrci field in the gap, = 0 as net flux cancels out

External EF = Q/eoA = 3*10^-12/(8.85*10^-12 * 5*10^-4

E = 687 N/C

force = kq1q2/r^2 = 9e9 * 3*3*10^-24/0.5^2*10^-6

FORCE F = 3.24*10^-7 N

b,. EF = Kq/r^2

Ef just outsde the bubble = 9e9* 1nC/0.03^2 = 10,000 N./C

just inside also 10000N/C

pressrue = Force/area

pressure = Eq/area = 5000* 1nC/4pi0.03^2 = 4.42*10^-4 N/m^2

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