A child of mass kg sits at the end of a rope of length m. The other end of the r

Q: A child of mass kg sits at the end of a rope of length m. The other end of the r

c) Ty = T sin theta Tx = T cos theta mgy = - mg mgx = 0 d) ay = 0 cos theta = r/L theta = arcos(2.5/3.2) T sin theta - m g = 0 T*sin(arcos(2.5/3.2)) - 47*9.81=0 T=738.6 N

ID: 2141218 • Letter: A

Question

A child of mass

kg sits at the end of a rope of length

m. The other end of the rope is fastened to a ceiling in a gymnasium, and the child travels so that he moves in a horizontal circle of radius

m as sketched in the figure below.

Ty = Tx = mgy = mgx = A child of mass m = 47 kg sits at the end of a rope of length L = 3.2 m. The other end of the rope is fastened to a ceiling in a gymnasium, and the child travels so that he moves in a orizontal circle of radius r = 2.50 m as sketched in the figure below.

Explanation / Answer

c) Ty = T sin theta

Tx = T cos theta

mgy = - mg

mgx = 0

ay = 0

cos theta = r/L

theta = arcos(2.5/3.2)

T sin theta - m g = 0

T*sin(arcos(2.5/3.2)) - 47*9.81=0

T=738.6 N

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A child of mass kg sits at the end of a rope of length m. The other end of the r

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