A CD with a diameter of 12.0 cm starts from rest and with a constant angular acc

Question

A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular deceleration. What is the total acceleration of a point 4.00 cm from the center at the time 10.0 seconds from the start? 0.65 m/s2 1.37 m/s2 1.86 m/s2 1.00 m/s2 1.25 m/s2 A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular deceleration. What is the total acceleration of a point 4.00 cm from the center at the time 10.0 seconds from the start? 0.65 m/s2 A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular deceleration. What is the total acceleration of a point 4.00 cm from the center at the time 10.0 seconds from the start? 0.65 m/s2 A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular deceleration. What is the total acceleration of a point 4.00 cm from the center at the time 10.0 seconds from the start? 0.65 m/s2 A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular deceleration. What is the total acceleration of a point 4.00 cm from the center at the time 10.0 seconds from the start? 0.65 m/s2 1.37 m/s2 1.86 m/s2 1.00 m/s2 1.25 m/s2 1.37 m/s2 1.86 m/s2 1.00 m/s2 1.25 m/s2 1.37 m/s2 1.86 m/s2 1.00 m/s2 1.25 m/s2 1.25 m/s2 1.25 m/s2

Explanation / Answer

at t = 10 s,

anglular speed = 5 rad/s

the point distance = 0.04 m

so, centripetal acceleration = 5^2*0.04 = 1 m/s2

tangential acceleration = 1*0.04 = 0.04 m/s2

so, total acceleration = sqrt(1^2+0.04^2) = 1 m/s2 <------answer

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