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The inductance of a solenoid with 460 turns and a length of 20 c m is 7.5 m H .

ID: 2140739 • Letter: T

Question

The inductance of a solenoid with 460 turns and a length of 20cm is 7.5mH . Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

The inductance of a solenoid with 460 turns and a length of 20cm is 7.5mH . The inductance of a solenoid with 460 turns and a length of 20cm is 7.5mH . The inductance of a solenoid with 460 turns and a length of 20cm is 7.5mH . The inductance of a solenoid with 460 turns and a length of 20cm is 7.5mH . Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

A=                                                  m^2

A=                                                  m^2

The inductance of a solenoid with 460 turns and a length of 20cm is 7.5mH . Part A What is the cross-sectional area of the solenoid? Express your answer using two significant figures. A=                                                  m^2

Explanation / Answer

L = uN^2A/l

So, A = Ll/uN^2 = 0.0075*0.2/(1.26*10^-6*460^2)

= 5.6*10^-3 m2 <--------answer