A car of mass M = 1500 k g traveling at 40.0 k m / h o u r enters a banked turn

Question

A car of mass M = 1500kg                     traveling at 40.0km/hour enters a banked                     turn covered with ice. The road is banked at an angle ?, and                     there is no friction between the road and the car's tires.

What is ?min, the minimum value of the coefficient of static friction between the tires and the road required to prevent the car from slipping? Assume that the car's speed is still 40.0km/hour  and that the radius of the curve is given by the value you found for r in Part A.

part a was 34.6m

answer needs to be numerically

Explanation / Answer

a) mv^2/r cos(theta) = mgsin(theta)

v^2/r = gtan(theta)

r = v^2/tan20*g = 34.61 m

b) mv^2/r cos20 = friction +mgsin20

frcition = u*mgcos20

mv^2/r cos20 = u*mgcos20 +mgsin20

11.111^2/34.61*cos20 = 9.8(u*cos20 + sin20)

3.352 = 9.8(ucos20 + sin20)

0.342 = ucos20 +sin20

u = 1.734x10^-5 = 0.00001724

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